(2x^2)+(2y^2)=3

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Solution for (2x^2)+(2y^2)=3 equation:


Simplifying
(2x2) + (2y2) = 3

Solving
(2x2) + (2y2) = 3

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '(-2y2)' to each side of the equation.
(2x2) + (2y2) + (-2y2) = 3 + (-2y2)

Combine like terms: (2y2) + (-2y2) = 0
(2x2) + 0 = 3 + (-2y2)
(2x2) = 3 + (-2y2)

Divide each side by '2'.
x2 = 1.5 + (-1y2)

Simplifying
x2 = 1.5 + (-1y2)
x2 + -1.5 + y2 = 1.5 + (-1y2) + -1.5 + (y2)

Reorder the terms:
-1.5 + x2 + y2 = 1.5 + (-1y2) + -1.5 + (y2)
-1.5 + x2 + y2 = 1.5 + (-1y2) + -1.5 + y2

Reorder the terms:
-1.5 + x2 + y2 = 1.5 + -1.5 + (-1y2) + y2

Combine like terms: 1.5 + -1.5 = 0.0
-1.5 + x2 + y2 = 0.0 + (-1y2) + y2
-1.5 + x2 + y2 = (-1y2) + y2

Combine like terms: (-1y2) + y2 = 0
-1.5 + x2 + y2 = 0

The solution to this equation could not be determined.

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